We need to come up with an expression for our area of that rectangle, so the with that rectangle delta y. The area is measured in square feet and the y or the depth is measured in feet, and this works out for a unit because feet squared times feet would be feet cubed and that would cancel out with these feet cube down here and then we're left with Pounds, which is what force will be measured in so our force is then just 62.4. We would need to multiply that by the area times the depth. So the force is that 62.4 pounds per cubic foot. Why? How far down is that from the top? Let that be y and we left the thickness of this part, be delta y, and then it's also going to depend on the length of that section or the area of that rectangle the length times its width. So if we had a thin layer of water swimming, that's filled with water and there's a here's gonna be a thin layer of that water to find the force the hydrostatic force on that section. We have these 4 lines containing the this area and that's representing the flat vertical side of a tank.
There is y equals 0 point, so we can see. Minus 4 and then the line y equals 0 would just be the x axis there. So here we have the line y equals 14 point. Each unit in the coordinate plane represents 1 foot and water has a density of 62.4 per cubic foot. Minus 4 y equals negative 2 x minus 4 and y equals 14 point. Find the hydrostatic force on the flat vertical side of a tank that is bounded by the lines y equals 0 y equals 2 x.
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